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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.     const char *p1, *p2, *s1 = "foobar", *s2 = "foobaz";
  5.     for (p1 = s1, p2 = s2 ; *p1 && *p1 == *p2 ; p1++, p2++);
  6.     const char *p = *p1 || *p2 ? p1 : NULL;
  7.     if (!p)
  8.         puts("the strings are equal");
  9.     else
  10.         printf("s1 has %c, where s2 has %c\n", *p, s2[p - s1]);
  11. 	return 0;
  12. }
  13.  
Success #stdin #stdout 0s 2292KB
comments (?)
stdin 
Standard input is empty
stdout 
s1 has r, where s2 has z
https://ideone.com/g0epf9
language:
C99 (gcc 8.3)
created:
11 years ago
visibility:
public

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