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  1.  
  2. #include <stdio.h>
  3. int main(void)
  4. {
  5.     int   i, n;
  6.     long p=1;
  7.     printf("请输入一个整数:\n");
  8.     scanf("%d", &n);
  9.     for (i=1; i<=n; i++)
  10.     {
  11.         p=p*i;                   
  12.     }
  13.     printf("%d! = %ld\n", n, p);
  14.     return 0;
  15. }
Success #stdin #stdout 0s 5332KB
comments (?)
stdin 
6
stdout 
请输入一个整数:
6! = 720
https://ideone.com/eDDJt4
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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