//	Please write a program using C++ that prints the integers counting down from 95 to 1. 
//	If the number is a multiple of 7, instead of the number, print Bizz. 
//	If the sum of the number with the previous Bizzed number is a multiple of 5, print Fuzz. 
//	If the number is both a multiple of 7 and its sum with the previous Bizzed number is a multiple of 5, 
//	 print BizzFuzz. This counts as a Bizzed number.
 
#include <stdio.h>
 
int main() {
	int lastBizzedNum = 0;
	for(int i=95;i>0;i--) {
		bool bizz = (i % 7) == 0;
		bool fuzz = (i + lastBizzedNum) % 5 == 0;
		const char* message = 0;
		switch ((bizz?1:0) + (fuzz?2:0)) {
			case 3:
				message = "BizzFuzz";
				lastBizzedNum = i;
				break;
			case 2:
				message = "Fuzz";
				break;
			case 1:
				message = "Bizz";
				break;		
		}
		if (message) {
			printf("%s\n", message);
		} else {
			printf("%d\n", i);
		}
	}
	return 0;
}
 

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