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function v = f(v)
	v(mod(v, 2) == 1) = sort(v(mod(v, 2) == 1));
	v(mod(v, 2) == 0) = flip(sort(v(mod(v, 2) == 0))) / 2;
end
f([0 9 8 4 6 5 1 2 7 3])

Success #stdin #stdout 0.14s 45664KB

stdin

Standard input is empty

stdout

ans =

   4   1   3   2   1   3   5   0   7   9

https://ideone.com/d5NTlm

language:

Octave (octave 4.4.1)

created:

visibility:

secret

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