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  1. #include <stdio.h>
  2. //a{n+1} = -2a{n} + 4, a{0}=2(再帰あり版)
  3. int rec(int n){
  4. 	int an=2;
  5. 	for(int i=0;i<n;i++){
  6. 		an=-2*an+4;
  7. 	}
  8. 	return an;
  9. }
  10. int main(void) {
  11.     int n=4;
  12.     printf("数列a%dの値は%d\n", n, rec(n));
  13.    	return 0;
  14. }
  15.  
  16.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin 
5
stdout 
数列a4の値は12
https://ideone.com/aQAnLM
language:
C (gcc 8.3)
created:
6 days ago
visibility:
public

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