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  1. def is_sorted(check):
  2.     ascending = True
  3.     descending = True
  4.     previous = check[0]
  5.     for item in check[1:]:
  6.         if ascending and item < previous:
  7.             ascending = False
  8.         if descending and item > previous:
  9.             descending = False
  10.         if not ascending and not descending:
  11.             return False
  12.         previous = item
  13.     return True
  14.  
  15. def test(check):
  16.     whether = is_sorted(check)
  17.     print(whether, check)
  18.  
  19. test([1, 2, 3, 4])
  20. test([1, 1, 1, 1])
  21. test([9, 8, 7, 6])
  22. test([1, 2, 3, 2])
Success #stdin #stdout 0.02s 7344KB
comments (?)
stdin 
Standard input is empty
stdout 
(True, [1, 2, 3, 4])
(True, [1, 1, 1, 1])
(True, [9, 8, 7, 6])
(False, [1, 2, 3, 2])
https://ideone.com/YjBB9T
https://stackoverflow.com/questions/66005621/check-if-list-is-sorted-in-either-ascending-or-descending-order-in-one-pass
language:
Python (cpython 2.7.16)
created:
4 years ago
visibility:
secret

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