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  1. #include <iostream>
  2. #include <math.h>
  3.  
  4. using namespace std;
  5. int n, liczba_nr[10000], i, x;
  6. int main()
  7. {
  8.     cin>>n;
  9.             for (int i=1;i<=n;i++)
  10.             {
  11.                 cin>>liczba_nr[i];
  12.             if ((liczba_nr[i]==2)||(liczba_nr[i]==3))
  13.                 cout<<"TAK"<<endl;
  14.             else if(liczba_nr[i]<3)
  15.                 cout<<"NIE"<<endl;
  16.             else if (liczba_nr[i]>3)
  17.                 {
  18.                 x=2;
  19.                 while (x<=sqrt(liczba_nr[i]))
  20.                     {
  21.                         if (liczba_nr[i]%x==0)
  22.                         {
  23.                         cout<<"NIE"<<endl;;
  24.                         break;
  25.                         }
  26.                         else
  27.                         {
  28.                         x++;
  29.                         if (x>sqrt(liczba_nr[i]))
  30.                             {
  31.                             cout<<"TAK"<<endl;
  32.                             }
  33.                         }
  34.                     }
  35.                 }
  36.  
  37.                }
  38.     return 0;
  39. }
  40.  
Success #stdin #stdout 0s 15272KB
comments (?)
stdin
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3
11
1
4
stdout
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TAK
NIE
NIE
https://ideone.com/YxRsBN
language:
C++ (gcc 8.3)
created:
5 years ago
visibility:
public

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