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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }
  7.     else{
  8.         return rec(n-2)+n;
  9.     }
  10. }
  11. int main(void) {
  12.     int n = 11;
  13.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  14. 	return 0;
  15. }
Success #stdin #stdout 0s 5284KB
comments (?)
stdin 
Standard input is empty
stdout 
11以下の正の奇数の和は36
https://ideone.com/Y1RqtH
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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