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  1. #!/bin/bash
  2. s="IP address one is 192.168.1.1, ip 2 is 192.168.1.2.
  3. 192.168.1.3  192.168.1.10.1"
  4. grep -Po '\b(?<!\d\.)(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b(?!\.\d)' <<< "$s"
  5.  
Success #stdin #stdout 0s 4408KB
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stdin
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Standard input is empty
stdout
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192.168.1.1
192.168.1.2
192.168.1.3
https://ideone.com/Y5kyIz
language:
Bash (bash 5.0.3)
created:
5 years ago
visibility:
secret

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