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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	// your code goes here
  6.  
  7. 	int sum=0;
  8. 	int init=10000000;
  9. 	int end=99999999;
  10. 	int *d=0;
  11.  
  12. 	for (int i=init; i<=end; i++) {
  13. 		int j=i;
  14. 		d = new int[10];
  15. 		while (j>0) {
  16. 			d[j%10]++;
  17. 			j/=10;
  18. 		}
  19. 		bool repeat = false;
  20. 		for (int k=0;k<=9;k++) {
  21. 			if (d[k]>=2) {
  22. 				repeat=true;
  23. 			}
  24. 		}
  25. 		if (!repeat) {
  26. 			if (i%3==0)
  27. 				sum++;
  28. 		}
  29. 		delete[] d;
  30. 	}
  31.  
  32. 	cout << sum;
  33. 	return 0;
  34. }
Success #stdin #stdout 4.57s 15232KB
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stdout 
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https://ideone.com/WxbaJt
Count the 8-distinct-digit 3-multiple numbers in range.
language:
C++ (gcc 8.3)
created:
7 years ago
visibility:
secret

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