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  1. f=->n{x=1
  2. b=*2..n*n
  3. n.times{b-=[x+=p(b.shift)]}}
  4.  
  5. f[100]
Success #stdin #stdout 0.11s 9552KB
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https://ideone.com/VIL5y5
language:
Ruby (ruby 2.5.5)
created:
9 years ago
visibility:
public

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