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  1. #include<iostream>
  2. #include<cmath>
  3. using namespace std;
  4. int main()
  5. {
  6.     int n;
  7.     cin>>n;
  8.     double a,b,c,d,res,h;
  9.     for(int i=0;i<n;i++)
  10.     {
  11.         cin>>a>>b>>c>>d;
  12.         h=((d*d)-(b*b)+abs((a-c)*(a-c)))/abs((2*a)-(2*c));
  13.         h=sqrt((d*d)-(h*h));
  14.         res=(a+c)*h;
  15.         res=0.5*res;
  16.         cout<<"Case "<<i+1<<": "<<res<<endl;
  17.     }
  18.     return 0;
  19. }
  20.  
Success #stdin #stdout 0s 3472KB
comments (?)
stdin 
2
6 5 12 5
9 5 6 4
stdout 
Case 1: 36
Case 2: 30
https://ideone.com/TcpRye
language:
C++ (gcc 8.3)
created:
9 years ago
visibility:
public

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