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  1. #include  <stdio.h>
  2. int main(void)
  3. {
  4.     int    data1, data2;
  5.     char  op;
  6.     printf("Please enter an expression:");
  7.     scanf("%d%c%d", &data1, &op, &data2);  
  8. switch (op)
  9. {
  10. case '+':
  11.    printf ("%d+%d=%d",data1,data2,data1+data2);
  12. case '-':
  13.     break;
  14.     printf ("%d-%d=%d",data1,data2,data1-data2);
  15.    break;
  16. case '*':
  17.     printf ("%d*%d=%d",data1,data2,data1*data2);
  18. break; 
  19. case '/':
  20.     if (data2==0)
  21.       printf ("除数为0，请重新输入");
  22.     else 
  23.        printf ("%d/%d=%d",data1,data2,data1/data2);
  24. break; 
  25. default: 
  26.    printf ("输入错误，请重新输入");
  27.  
  28.  
  29.  
  30. }
  31.  
  32.     return 0;
  33. }
  34.  
Success #stdin #stdout 0s 5284KB
comments (?)
stdin 
2+8
stdout 
Please enter an expression:2+8=10
https://ideone.com/Sp3Sk5
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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