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  1. #include <iostream>
  2. #include <assert.h> 
  3. #include <stdlib.h> 
  4. using namespace std;
  5.  
  6. class TriMat {
  7. 	private:
  8. 		int Size;	
  9. 		int** M;
  10. 	public:
  11. 		TriMat(int n) {
  12. 			Size = n;
  13. 			M = (int**) malloc(Size * sizeof(int));
  14. 			for (int k = 0; k < Size; k++) {
  15. 				M[k] = (int*) malloc((Size - k) * sizeof(int));
  16. 				for (int j = 0; j <= Size - 1 - k; j++)
  17. 					cin >> M[k][j];
  18. 			}
  19. 		}
  20.  
  21. 		// Конструктор скалярной матрицы с заданным элементом на главной диагонали
  22. 		TriMat(int n, int a) {
  23. 			Size = n;
  24. 			M = (int**) malloc(Size * sizeof(int));
  25. 			for (int k = 0; k < Size; k++) {
  26. 				M[k] = (int*) malloc((Size - k) * sizeof(int));
  27. 				M[k][0] = a;
  28. 			}
  29. 		}
  30.  
  31. 		void print() {
  32. 			for (int k = 0; k < Size; k++) {
  33. 				for (int j = 0; j < k; j++)
  34. 					cout << "\t";
  35. 				for (int j = 0; j <= Size - 1 - k; j++)
  36. 					cout << M[k][j] << "\t";
  37. 				cout << endl;
  38. 			}
  39. 		}
  40.  
  41.     	int* operator[](size_t k) {
  42.     		assert(0 <= k && k < Size);
  43.     		return M[k];
  44.     	}
  45.  
  46. 		void assign(int i, int j, int a) {
  47. 			assert(0 <= i && i < Size && 0 <= j && j < Size);
  48. 			M[i][j] = a;
  49. 		}
  50.  
  51. 		int el(int i, int j) {
  52. 			assert(0 <= i && i < Size && 0 <= j && j < Size);
  53. 			return M[i][j];
  54. 		}
  55.  
  56.  
  57. 		TriMat operator+ (TriMat B) {
  58. 			TriMat C(Size);
  59. 			for (int k = 0; k < Size; k++)
  60. 				for (int j = 0; j <= Size - 1 - k; j++)
  61. 					C[k][j] = M[k][j] + B[k][j];
  62. 			return C;
  63. 		}
  64.  
  65. 		TriMat operator= (TriMat B) {
  66. 			for (int k = 0; k < Size; k++)
  67. 				for (int j = 0; j <= Size - 1 - k; j++)
  68. 				M[k][j] = B[k][j];
  69. 			return *this;
  70. 		}
  71.  
  72. 		TriMat operator* (TriMat B) {
  73. 			TriMat C(Size);
  74. 			for (int k = 0; k < Size; k++)
  75. 				for (int j = k; j < Size; j++) {
  76. 					for (int r = k; r <= j; r++)
  77. 						C[k][j-k] += M[k][r-k] * B[r][j-r];
  78. 				}
  79. 			return C;
  80. 		}
  81. };
  82.  
  83.  
  84. int main() {
  85. 	int n;
  86. 	cin >> n;
  87. 	TriMat A(n), B(n), I(n,1), C = A * (I + B*B);
  88. 	A.print();
  89. 	B.print();
  90. 	C.print();
  91. 	return 0;
  92. }
Success #stdin #stdout 0s 3420KB
comments (?)
stdin
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3
2 2 2
   0 3
      1
1 2 3
   4 5
      6
stdout
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2	2	2	
	0	3	
		1	
1	2	3	
	4	5	
		6	
4	54	236	
	0	111	
		37
https://ideone.com/QomEh3
language:
C++ (gcc 8.3)
created:
8 years ago
visibility:
secret

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