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  1. p={x->(2..<x).every{x%it!=0}&x>1|x==2}
  2. f={x->(1..x).findAll({y->p(y)&'10'.every{p(Integer.toBinaryString(y).count(it))}})}
  3. [10,100,150,17].each{println f(it)}
Success #stdin #stdout 0.64s 333376KB
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[]
[17, 19, 37, 41, 79]
[17, 19, 37, 41, 79, 103, 107, 109, 131, 137]
[17]
https://ideone.com/LWnXW3
language:
Groovy (groovy 2.5.6)
created:
7 years ago
visibility:
public

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