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  1. import re
  2. s = ("It costs 2. 5. That is a lot.\n"
  3. 	"It costs 2. 5 items, that is a lot.")
  4. pattern = r"\b(\d+\.)[^\S\r\n]+(\d+\.)"
  5. print(re.sub(pattern, r"\1\2", s))
Success #stdin #stdout 0.02s 9576KB
comments (?)
stdin 
Standard input is empty
stdout 
It costs 2.5. That is a lot.
It costs 2. 5 items, that is a lot.
https://ideone.com/LunrE2
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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