fork(1) download 
  1. import re
  2.  
  3. def re_rsplit(pattern, text, maxsplit):
  4.     if maxsplit < 1 or not pattern.search(text): # If split is 0 or less, or upon no match
  5.         return [text]                            # Return the string itself as a one-item list
  6.     prev = len(text)                             # Previous match value start position
  7.     cnt = 0                                      # A match counter
  8.     result = []                                  # Output list
  9.     for m in reversed(list(pattern.finditer(text))):
  10.         result.append(text[m.end():prev])        # Append a match to resulting list
  11.         prev = m.start()                         # Set previous match start position
  12.         cnt += 1                                 # Increment counter
  13.         if cnt == maxsplit:                      # Break out of for loop if...
  14.             break                                # ...match count equals max split value
  15.     result.append(text[:prev])                   # Append the text chunk from start
  16.     return reversed(result)                      # Return reversed list
  17.  
  18. splitme = "a!b?c!d"
  19. pattern = re.compile(r'[!?]')
  20. print(list(re_rsplit(pattern, splitme, -1))) # => ['a!b?c!d']
  21. print(list(re_rsplit(pattern, splitme, 0)))  # => ['a!b?c!d']
  22. print(list(re_rsplit(pattern, splitme, 1)))  # => ['a!b?c', 'd']
  23. print(list(re_rsplit(pattern, splitme, 2)))  # => ['a!b', 'c', 'd']
  24. print(list(re_rsplit(pattern, splitme, 3)))  # => ['a', 'b', 'c', 'd']
  25. print(list(re_rsplit(pattern, splitme, 50))) # => ['a', 'b', 'c', 'd']
Success #stdin #stdout 0.03s 9384KB
comments (?)
stdin 
Standard input is empty
stdout 
['a!b?c!d']
['a!b?c!d']
['a!b?c', 'd']
['a!b', 'c', 'd']
['a', 'b', 'c', 'd']
['a', 'b', 'c', 'd']
https://ideone.com/JRJKu7
language:
Python 3 (python  3.12)
created:
3 years ago
visibility:
public

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