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  1. #n = int(input())
  2. #a = list(map(int, input().split()))
  3. #m = int(input())
  4. #b = list(map(int, input().split()))
  5. #for i in range(m):
  6. #    print(a.count(b[i]))
  7.  
  8. def binSearch(arr,v):
  9. 	n=len(arr)
  10. 	left=0
  11. 	right=n-1
  12. 	count=0
  13. 	if v > arr[n-1]:
  14. 		return 0
  15. 	if v < arr[0]:
  16. 		return 0
  17. 	while(True):
  18. 		middle=(left+right)//2
  19. 		if arr[middle]==v:
  20. 			count+=1
  21. 			i=middle-1
  22. 			while (i >= 0) and (arr[i]==v):
  23. 				count+=1
  24. 				i-=1
  25. 			i=middle+1
  26. 			while (i < n) and (arr[i]==v):
  27. 				count+=1
  28. 				i+=1
  29. 			return count
  30. 		elif middle==left | middle==right:
  31. 			return count
  32. 		elif arr[middle] > v:
  33. 			right=middle
  34. 		else:
  35. 			left=middle
  36.  
  37. x=binSearch([1,2,2,2,3,3,4,5,6,6,6,6],6)		
  38. print(x)			
  39.  
Success #stdin #stdout 0.02s 9108KB
comments (?)
stdin 
Standard input is empty
stdout 
4
https://ideone.com/JQoWuj
Двоичный поиск
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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