#include <bits/stdc++.h> 
using namespace std;  
 
typedef long long ll;  
typedef pair<int, int> ii;  
 
const int INF = 1e9;  
const ll LINF = 1e18;  
 
const int N = 2e5 + 5; 
 
template<typename T>
void maximize(T& a, const T& b) {
	if (b < a) return;  
	a = b; 
}
 
struct project {
	int l, r; ll w; 
	bool operator<(const project& other) const {
		return (r < other.r); 
	}
}; 
 
int n; 
project a[N]; 
 
ll dp[N]; // dp[i] = Lợi nhuận lớn nhất đạt được khi xét i dự án đầu tiên
 
// Tìm vị trí i lớn nhất sao cho a[i].r < x
int binSearch(int l, int r, int x) {
	int ans = -1; 
	while (l <= r) {
		int mid = (l + r) >> 1; 
		if (a[mid].r < x) {
			ans = mid;   
			l = mid + 1; 
		}
		else {
			r = mid - 1; 
		}
	}
	return ans; 
}
 
int main() {
	ios::sync_with_stdio(0); cin.tie(0);  	
	cin >> n; 
	for (int i = 1; i <= n; i++) {
		cin >> a[i].l >> a[i].r >> a[i].w; 
	}
 
	// sort tăng dần theo thời điểm kết thúc của các dự án 
	sort(a + 1, a + n + 1);  
 
	for (int i = 1; i <= n; i++) {
		// không chọn dự án thứ i 
		dp[i] = dp[i - 1]; 
		// chỉ chọn dự án thứ i 
		maximize(dp[i], a[i].w);
		// chọn dự án thứ i cùng với một số dự án khác ở trước   
		int prev_i = binSearch(1, i - 1, a[i].l);
		if (prev_i != -1) maximize(dp[i], dp[prev_i] + a[i].w);  
	}
 
	cout << dp[n] << '\n'; 
}

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4
2 4 4
3 6 6
6 8 2
5 7 3