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  1. #include <iostream>
  2. #include <cstring>
  3. #include <sstream>
  4. using namespace std;
  5.  
  6. union Conversor {
  7.     char bytes[sizeof( double )];
  8.     double x;
  9. };
  10.  
  11. int main()
  12. {
  13. 	char bytes[sizeof(double)];
  14. 	double x = 32.121;
  15.  
  16. 	cout << "Sizeof char: " << sizeof( char ) << endl;
  17. 	cout << "Sizeof double: " << sizeof( double ) << endl;
  18.  
  19. 	// Copying memory
  20. 	memcpy( bytes, &x, sizeof(x) );
  21.  
  22. 	for(int i = 0; i < sizeof( x ); ++i) {
  23. 		cout << bytes[ i ] << ' ';	
  24. 	}
  25.  
  26. 	// Using a union
  27. 	Conversor cnvt;
  28. 	cnvt.x = x;
  29.  
  30. 	for(int i = 0; i < sizeof( x ); ++i) {
  31. 		cout << cnvt.bytes[ i ] << ' ';	
  32. 	}
  33.  
  34. 	// Just text conversion
  35. 	ostringstream cnvt2;
  36.  
  37.     cnvt2 << 32.121;
  38.     cout << cnvt2.str() << endl;
  39.  
  40.  
  41. 	cout << endl;
  42. 	return 0;
  43. }
  44.  
Success #stdin #stdout 0s 15240KB
comments (?)
stdin
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Standard input is empty
stdout
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Sizeof char: 1
Sizeof double: 8
s h � � |  @ @ s h � � |  @ @ 32.121
https://ideone.com/IPWCxs
Convertir de double a array de char.
language:
C++ (gcc 8.3)
created:
6 years ago
visibility:
public

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