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  1. import re
  2. newtxt="200 sample text with many lines\n hell01 \n hell02 \n hell03 \n hell04 \n hell05\n hell06\n hell07 \n hell08"
  3. pattern = re.compile(r'^\d{3} [a-z].*((?:\r?\n.*){0,5})', re.M)
  4. m = pattern.search(newtxt)
  5. if m:
  6.   print( m.group(1) )
Success #stdin #stdout 0.02s 9616KB
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stdin
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Standard input is empty
stdout
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 hell01 
 hell02 
 hell03 
 hell04 
 hell05
https://ideone.com/HFDKbM
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
public

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