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  1. #include <bits/stdc++.h> // NeOWami
  2. using namespace std;
  3.  
  4. #define ft first
  5. #define sc second
  6. #define int long long
  7. const int N = 1e5 + 5;
  8. const int LG = 18;
  9. int n, d[N], a[N][LG], q;
  10.  
  11. namespace sub1 {
  12. void solve() {
  13. while (q--) {
  14. int type, u, v; cin >> type >> u >> v;
  15. if (type == 0) {
  16. int t; cin >> t;
  17. for (int i = u; i <= v; i++) d[i] ^= t;
  18. }
  19. else {
  20. int ans = 0;
  21. for (int i = u; i <= v; i++) ans += d[i];
  22. cout << ans << "\n";
  23. }
  24. }
  25. }
  26. }
  27. namespace subfull {
  28. int st[N * 4][2][LG];
  29. void calc(int id, int len, int i) {
  30. st[id][0][i] = len - st[id][0][i];
  31. st[id][1][i] = !st[id][1][i];
  32. }
  33.  
  34. void down(int id, int l, int r) {
  35. int mid = l + r >> 1;
  36. for (int i = 0; i < LG; i++) if (st[id][1][i]) {
  37. calc(id * 2, mid - l + 1, i);
  38. calc(id * 2 + 1, r - mid, i);
  39. st[id][1][i] = 0;
  40. }
  41. }
  42. void build(int id, int l, int r) {
  43. if (l == r) {
  44. for (int i = 0; i < LG; i++) st[id][0][i] = a[l][i];
  45. return;
  46. }
  47. int mid = l + r >> 1;
  48. build(id * 2, l, mid);
  49. build(id * 2 + 1, mid + 1, r);
  50. for (int i = 0; i < LG; i++) st[id][0][i] = st[id * 2][0][i] + st[id * 2 + 1][0][i];
  51. }
  52.  
  53. void update(int id, int l, int r, int u, int v, int p) {
  54. if (l > v || r < u) return;
  55. if (l >= u && r <= v) {
  56. for (int i = 0; i < LG; i++) if (p >> i & 1) calc(id, r - l + 1, i);
  57. return;
  58. }
  59. down(id, l, r);
  60. int mid = l + r >> 1;
  61. update(id * 2, l, mid, u, v, p);
  62. update(id * 2 + 1, mid + 1, r, u, v, p);
  63. for (int i = 0; i < LG; i++) st[id][0][i] = st[id * 2][0][i] + st[id * 2 + 1][0][i];
  64. }
  65.  
  66. int get(int id, int l, int r, int u, int v) {
  67. if (l > v || r < u) return 0;
  68. if (l >= u && r <= v) {
  69. int ans = 0;
  70. for (int i = 0; i < LG; i++) ans += (1 << i) * st[id][0][i];
  71. return ans;
  72. }
  73. down(id, l, r);
  74. int mid = l + r >> 1;
  75. return get(id * 2, l, mid, u, v) + get(id * 2 + 1, mid + 1, r, u, v);
  76. }
  77. void solve() {
  78. for (int i = 1; i <= n; i++) {
  79. int x = d[i];
  80. for (int j = 0; j < LG; j++) a[i][j] = (x >> j) & 1;
  81. }
  82. build(1, 1, n);
  83. while (q--) {
  84. int type, u, v; cin >> type >> u >> v;
  85. if (type == 0) {
  86. int t; cin >> t;
  87. update(1, 1, n, u, v, t);
  88. }
  89. else cout << get(1, 1, n, u, v) << "\n";
  90. }
  91. }
  92. }
  93. signed main() {
  94. cin.tie(NULL)->sync_with_stdio(false);
  95. if(ifstream("LZXOR.inp")) {
  96. freopen("LZXOR.inp", "r", stdin);
  97. freopen("LZXOR.out", "w", stdout);
  98. }
  99. cin >> n;
  100. for (int i = 1; i <= n; i++) cin >> d[i];
  101. cin >> q;
  102. if (n * q <= 1'000'000) return sub1::solve(), 0;
  103. return subfull::solve(), 0;
  104. return 0;
  105. }
Success #stdin #stdout 0s 5312KB
stdin
Standard input is empty
stdout
Standard output is empty