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  1. #include<stdio.h>
  2. #include<string.h>
  3.  
  4. struct data{
  5. 	char name[150];
  6. 	int score;	
  7. };
  8.  
  9. void swap(int *a,int *b){
  10. 	int temp;
  11. 	temp=*a;
  12. 	*a=*b;
  13. 	*b=temp;
  14. }
  15.  
  16. void nameswap(char str1[], char str2[]){
  17.     char temp[100];
  18.     strcpy(temp, str1);
  19.     strcpy(str1, str2);
  20.     strcpy(str2, temp);
  21. }
  22.  
  23. void bubble(struct data x[],int n){
  24. 	for(int i=0;i<n-1;i++){
  25. 		for(int j=0;j<n-1-i;j++){
  26. 			if(x[j].score<x[j+1].score){
  27. 				swap(&x[j].score,&x[j+1].score);
  28. 				nameswap(x[j].name,x[j+1].name);
  29. 			}
  30. 			else if(x[j].score==x[j+1].score &&strcmp(x[j].name,x[j+1].name)>0){
  31. 				swap(&x[j].score,&x[j+1].score);
  32. 				nameswap(x[j].name,x[j+1].name);
  33. 			}
  34. 		}
  35. 	}
  36. }
  37.  
  38. int main(){
  39. 	struct data x[1000];
  40. 	int n,t;
  41. 	char kata[100];
  42. 	scanf("%d",&t);
  43. 	for(int i=0;i<t;i++){
  44. 		scanf("%d",&n);
  45. 		getchar();
  46. 		for(int j=0;j<n;j++){
  47. 			scanf("%[^#]#%d",x[j].name,&x[j].score);
  48. 			getchar();
  49. 		}
  50. 		scanf("%s",kata);
  51. 		bubble(x,n);
  52. 		for(int k=0;k<n;k++){
  53. 			if(strcmp(kata,x[k].name)==0){
  54. 				printf("Case #%d: %d\n",i+1,k+1);
  55. 				break;
  56. 			}
  57. 		}
  58. 	}
  59. 	return 0;
  60. }
Success #stdin #stdout 0s 5472KB
comments (?)
stdin 
2
3
Jojo#40
Lili#80
Bibi#90
Lili
3
Jojo#100
Lili#80
Bibi#90
Lili
stdout 
Case #1: 2
Case #2: 3
https://ideone.com/Ebe40P
language:
C (gcc 8.3)
created:
2 years ago
visibility:
public

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