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  1. def f(a)
  2.   b = a.select(&:odd?).sort
  3.   a.map {|n| n.odd? ? b.shift : n}
  4. end
  5. p f [6, 5, 4, 3, 2, 1]
  6. p f [6, 5, 3, 1]
  7.  
Success #stdin #stdout 0.01s 6476KB
comments (?)
stdin 
Standard input is empty
stdout 
[6, 1, 4, 3, 2, 5]
[6, 1, 3, 5]
https://ideone.com/EUWgwy
language:
Ruby (ruby 2.5.5)
created:
5 years ago
visibility:
secret

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