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  1. num = 909090909090909090909
  2.  
  3. def div11(n):
  4.     acc, sign = 0, 1
  5.  
  6.     while n:
  7.         n, r, sign = n // 10, n % 10, -sign
  8.         acc += r * sign
  9.  
  10.     acc = abs(acc)
  11.     return div11(acc) if acc >= 11 else acc == 0
  12.  
  13. if div11(num):
  14.     print('yes')
  15. else:
  16.     print('no')
  17.  
Success #stdin #stdout 0.02s 9316KB
comments (?)
stdin 
Standard input is empty
stdout 
yes
https://ideone.com/ERIPBC
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
secret

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