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  1. for _ in range(11):
  2. 	n=2;x=[]
  3. 	exec'x+=n/2*[1j**n];n+=1;'*input()
  4. 	print-sum(x[:n-2])
Success #stdin #stdout 0.02s 9080KB
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stdin
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0
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100
stdout
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0
(1-0j)
(1+1j)
(-0+1j)
(-1+1j)
(-1-0j)
(-1-1j)
(-0-1j)
(1-1j)
(2-1j)
(-5+5j)
https://ideone.com/EHfyPJ
language:
Python (cpython 2.7.16)
created:
7 years ago
visibility:
public

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