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  1. long long d;j,s=1,n,b[10]={1};long long f(n){return n?n*f(n-1):1;}main(d){for(scanf("%d",&n);--n;)for(j=n;j;j/=10)b[j%10]++,s++;for(;j<10;)d*=f(b[j++]);printf("%Ld",f(s)/d);}
Success #stdin #stdout 0s 2160KB
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stdin 
12
stdout 
1816214400
https://ideone.com/BpA81a
language:
C (gcc 8.3)
created:
9 years ago
visibility:
public

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