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  1. # leap seconds
  2. # http://c...content-available-to-author-only...e.com/questions/52452/leap-for-leap-seconds
  3.  
  4. n=0x410208002495288454aaab
  5. for i in range(88):
  6.     if n%2:print"%d-%02d-3%d 23:59:60"%(1972+i/2,i%2*6+6,i%2)
  7.     n/=2
Success #stdin #stdout 0.01s 7736KB
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Standard input is empty
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1972-06-30 23:59:60
1972-12-31 23:59:60
1973-12-31 23:59:60
1974-12-31 23:59:60
1975-12-31 23:59:60
1976-12-31 23:59:60
1977-12-31 23:59:60
1978-12-31 23:59:60
1979-12-31 23:59:60
1981-06-30 23:59:60
1982-06-30 23:59:60
1983-06-30 23:59:60
1985-06-30 23:59:60
1987-12-31 23:59:60
1989-12-31 23:59:60
1990-12-31 23:59:60
1992-06-30 23:59:60
1993-06-30 23:59:60
1994-06-30 23:59:60
1995-12-31 23:59:60
1997-06-30 23:59:60
1998-12-31 23:59:60
2005-12-31 23:59:60
2008-12-31 23:59:60
2012-06-30 23:59:60
2015-06-30 23:59:60
https://ideone.com/AGUrW8
Leap seconds: shortest
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
public

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