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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	cout<<"sizeof(\"x\") = " <<sizeof("x") <<endl<<"sizeof('x') = " <<sizeof('x') <<endl;
  6.  
  7. 	cout<<"Content of \"x\" are(in Hexadecimal): "<<endl;
  8. 	char x[] = "x";
  9. 	cout.setf(ios::hex, ios::basefield);
  10. 	for(int i=0; i<sizeof("x"); i++)
  11. 		 cout<<"\t "<<(int)x[i] <<endl;
  12. 	return 0;
  13. }
Success #stdin #stdout 0s 4400KB
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stdin
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Standard input is empty
stdout
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sizeof("x") = 2
sizeof('x') = 1
Content of "x" are(in Hexadecimal): 
	 78
	 0
https://ideone.com/OXu9ci
https://stackoverflow.com/questions/49525433/answer-review-invalid-conversion-from-const-char-to-char
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
secret

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