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  1. 	int main()
  2. 	{
  3. 		int M = 1000;
  4. 		int numbers[] = {17, 19, 23, 29, 31, 37};
  5. 		int N = sizeof(numbers) / sizeof(numbers[0]);
  6. 		int values[N+1], count = 0, i, v;
  7. 		for (i = N; i >= 0; i--) values[i] = 0;
  8.  
  9. 		while (1) {
  10. 			if ((M - values[0]) % numbers[0] == 0)
  11. 				count++;
  12. 			for (i = 1; i < N; i++) {
  13. 				v = values[i] + numbers[i];
  14. 				if (v > M) continue;
  15. 				break;
  16. 			}
  17. 			if (i == N) break;
  18. 			while (i >= 0) values[i--] = v;
  19. 		}
  20.  
  21. 		printf("count = %d\n", count);
  22.  
  23. 		return 0;
  24. 	}
  25.  
Success #stdin #stdout 0s 9432KB
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stdin 
Standard input is empty
stdout 
count = 48939
https://ideone.com/O5OwR7
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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