//Q93. Check if two strings are anagrams of each other.
#include <stdio.h>
#include <string.h>
 
int main() {
    char str1[100], str2[100];
    int freq[26] = {0}, i;
 
        return 0;
    }
 
    for(i=0; str1[i]!='\0'; i++) {
        freq[str1[i]-'a']++;
        freq[str2[i]-'a']--;
    }
 
    for(i=0; i<26; i++) {
        if(freq[i] != 0) {
            return 0;
        }
    }
 
}
 
				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