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  1. #include <stdio.h>
  2. //a{n+1} = -2a{n} + 4, a{0}=2(再帰なし版)
  3. int main(void) {
  4.     int n ;
  5.     int an;
  6.     scanf("%d",&an);
  7.     scanf("%d",&n);
  8. 	for(int i=0;i<n;i++){
  9. 		an=-2*an+4;
  10. 	}
  11.     printf("数列a%dの値は%d\n", n, an);
  12.  
  13. 	return 0;
  14. }
  15.  
  16.  
Success #stdin #stdout 0.01s 5284KB
comments (?)
stdin 
2
4
stdout 
数列a4の値は12
https://ideone.com/N3Ctpb
language:
C (gcc 8.3)
created:
84 days ago
visibility:
public

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