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  1. string = "1 chocolate bar at 25"
  2. p string.match(/(\d+) +(\D+) +at +(\d+)/).captures
Success #stdin #stdout 0s 28688KB
comments (?)
stdin 
Standard input is empty
stdout 
["1", "chocolate bar", "25"]
https://ideone.com/Mgzjrz
language:
Ruby (ruby 2.5.5)
created:
8 years ago
visibility:
secret

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