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  1. import re
  2.  
  3. texts = ['1. 10.25% 2. 11% 3. 9.75% 4. 4.3%',
  4. '1.promising.2.inappropriately3.essential.4.itense.',
  5. '1. He has not been attending 2. English classes 3. since one month4. No error',
  6. '1. X got 15 shares2. B got 25 shares3. W got 54. shares.4. Mark got 2.5 shares']
  7.  
  8. pattern = r'(?<!\d){}\.'
  9. for text in texts:
  10. 	bps = []
  11. 	prev = 0
  12. 	for i in range(1,1000):
  13. 		rx = re.compile(pattern.format(i))
  14. 		m = rx.search(text, prev)
  15. 		if m:
  16. 			if prev != m.start():
  17. 			    bps.append(text[prev:m.start()].strip())
  18. 			prev = m.start()
  19. 		else:
  20. 			break
  21. 	if prev < len(text) - 1:
  22. 		bps.append(text[prev:].strip())
  23. 	print(bps)
Success #stdin #stdout 0.02s 9504KB
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['1. 10.25%', '2. 11%', '3. 9.75%', '4. 4.3%']
['1.promising.', '2.inappropriately', '3.essential.', '4.itense.']
['1. He has not been attending', '2. English classes', '3. since one month', '4. No error']
['1. X got 15 shares', '2. B got 25 shares', '3. W got 54. shares.', '4. Mark got 2.5 shares']
https://ideone.com/8tqFll
language:
Python 3 (python  3.12)
created:
4 years ago
visibility:
secret

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