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  1. #Square Root
  2. def sqrt( n ):
  3.  
  4.     x = n
  5.     y = 1.0
  6.     eps = 0.000001
  7.  
  8.     while x - y > eps:
  9.         x = (x + y) / 2
  10.         y = n / x
  11.     return x
  12.  
  13. # ax^2 + bx + c = 0
  14. def QuadraticEquation(a, b, c):
  15.     if a != 0:
  16.         discriminant = b ** 2 - 4 * a * c
  17.         if discriminant > 0 and a > 0:
  18.             root1 = (-b - sqrt(discriminant))/(2*a)
  19.             root2 = (-b + sqrt(discriminant))/(2*a)
  20.             return 2, root1, root2
  21.         elif discriminant > 0 and a < 0:
  22.             root1 = (-b + sqrt(discriminant))/(2*a)
  23.             root2 = (-b - sqrt(discriminant))/(2*a)
  24.             return 2, root1, root2
  25.         elif discriminant == 0:
  26.             root1 = root2 = -b/(2*a)
  27.             return 1, root1
  28.         else:
  29.             return [0]
  30.     else:
  31.         if b == 0 and c == 0:
  32.             return [-1]
  33.         elif b != 0:
  34.             root1 = -c/b
  35.             return [1, root1]
  36.         else:
  37.             return[0]
  38. A, B, C = [int(i) for i in input().split()]
  39. print(*QuadraticEquation(A, B, C), sep='\n')
Success #stdin #stdout 0.03s 9868KB
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stdin
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1223 -23532 1232
stdout
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2
0.05249747447913724
19.188712664523315
https://ideone.com/7UKwDM
Quadratic Equation
language:
Python 3 (python  3.9.5)
created:
1 year ago
visibility:
secret

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