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  1. def imp(a, b):
  2.     return not a or b
  3.  
  4. rows = [(0,'?',0,0,0,1), (0,0,0,'?',0,'?'), (0,1,1,'?','?',0)]
  5.  
  6. for a in 'xyzw':
  7.     for b in 'xyzw':
  8.         for c in 'xyzw':
  9.             for d in 'xyzw':
  10.                 if len({a, b, c, d}) < 4:
  11.                     continue
  12.                 ok = True
  13.                 for row in rows:
  14.                     found = False
  15.                     for n in range(16):
  16.                         v = {'x': n >> 3 & 1, 'y': n >> 2 & 1, 'z': n >> 1 & 1, 'w': n & 1}
  17.                         x, y, z, w = v['x'], v['y'], v['z'], v['w']
  18.                         t = [v[a], v[b], v[c], v[d],
  19.                              int(imp(w, y) == imp(z, x)),
  20.                              int(imp(w, y) and (not x) == z)]
  21.                         match = True
  22.                         for i in range(6):
  23.                             if row[i] != '?' and row[i] != t[i]:
  24.                                 match = False
  25.                         if match:
  26.                             found = True
  27.                     if not found:
  28.                         ok = False
  29.                 if ok:
  30.                     print(a + b + c + d)
Success #stdin #stdout 0.02s 9408KB
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yzxw
https://ideone.com/6EWRlA
language:
Python 3 nbc (python 3.7.3)
created:
52 minutes ago
visibility:
public

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