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  1. import java.util.regex.Matcher;
  2. import java.util.regex.Pattern;
  3.  
  4. public class Main {
  5. 	public static void main(String[] args) {
  6. 		// Tests
  7. 		String[] samples = { "123ABC458", "123ABC458XYZ", "123ABC458XYZ367", "ABC123XYZ", "ABC123XYZ" };
  8. 		for (String s : samples)
  9. 			System.out.println(numbersInverted(s));
  10.  
  11. 	}
  12.  
  13. 	static String numbersInverted(String str) {
  14. 		StringBuilder sb = new StringBuilder();
  15. 		Matcher matcher = Pattern.compile("\\d+").matcher(str);
  16. 		int lastInitialPos = 0;
  17. 		while (matcher.find()) {
  18. 			int start = matcher.start();
  19. 			String inverted = new StringBuilder(matcher.group()).reverse().toString();
  20. 			sb.append(str.substring(lastInitialPos, start)).append(inverted);
  21. 			lastInitialPos = matcher.end();
  22. 		}
  23. 		if (sb.length() == 0) // If no number was found
  24. 			return str;
  25. 		else
  26. 			return sb.append(str.substring(lastInitialPos)).toString();
  27. 	}
  28. }
Success #stdin #stdout 0.09s 48024KB
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stdin
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Standard input is empty
stdout
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321ABC854
321ABC854XYZ
321ABC854XYZ763
ABC321XYZ
ABC321XYZ
https://ideone.com/4iPO7h
language:
Java (HotSpot 12)
created:
4 years ago
visibility:
public

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