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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5. 			int l, a, n, p;
  6. 			scanf ("%d\n",&l);
  7.             for (a = l%2, p = getchar()>'9'; --l; n = p ^ getchar()>'9', a &= (p^=n)^n^p );
  8.             printf("%d", a);
  9.  
  10.             return 0;
  11. }
  12.  
Success #stdin #stdout 0s 2116KB
comments (?)
stdin
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9
h2h3h5h5h
stdout
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1
https://ideone.com/3fWW1w
language:
C (gcc 8.3)
created:
10 years ago
visibility:
public

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