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  1. import re
  2.  
  3. finalcontent=' £2,500 and also £ 1200 and also £ 7,645 and finally £8888 and london'
  4. print( re.findall(r'£\s*(\d+(?:\.\d+)?)',finalcontent.replace(',','')) )
  5.  
Success #stdin #stdout 0.02s 9636KB
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['2500', '1200', '7645', '8888']
https://ideone.com/25lAU0
language:
Python 3 (python  3.12)
created:
5 years ago
visibility:
secret

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