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  1. #include <stdio.h>
  2. double power(double x,int n){
  3.     double p=1;
  4.     int i;
  5.     for(i=1;i<=n;i++)
  6.     p=p*n;
  7.     return p;
  8. }
  9. int main(void) {
  10. 	double a;
  11.     int b;
  12.     int m;
  13.     scanf("%d%d\n",&a,&b);
  14.     m=power(a,b);
  15.     printf("%d的%d次方是：%d",a,b,m);
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5360KB
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3  2
stdout
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2的4次方是：-492451647
https://ideone.com/zNchrr
language:
C (gcc 8.3)
created:
4 hours ago
visibility:
public

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