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#include <memory>
#include <iostream>
 
using namespace std;
 
template <class T>
class B 
{
public:
  void outB() { cout << "dim from B is " << dim_ << endl ; }
  B(int dim) : dim_(dim) {}
  ~B() {}
protected:
  int dim_;
};
 
template <class T>
class A : B<T>
{
public:
  using B<T>::dim_;
//  using B<T>::outB;
  void outA() { cout << "dim from A is " << dim_ << endl ; }
  A(int dim) : B<T>(dim) {}
  ~A() {}
private:
};
 
 
int main(int argc, const char *argv[])
{
  shared_ptr<A<double> > ap(new A<double>(2));
  ap->outA();
  ap->outB();
  return 0;
}

prog.cpp: In function 'int main(int, const char**)':
prog.cpp:10:8: error: 'void B<T>::outB() [with T = double]' is inaccessible
prog.cpp:34:12: error: within this context
prog.cpp:34:12: error: 'B<double>' is not an accessible base of 'A<double>'

Standard output is empty