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  1. memo=[]
  2. def func(n)
  3. 	r=0
  4. 	while(n!=3)
  5. 		n=(n%2==0)?n/=2:(n+1)*3
  6. 		r+=1
  7. 	end
  8. 	r
  9. end
  10.  
  11. maxv=maxi=0
  12. 2.upto(10000){|n|
  13. 	w=func(n)
  14. 	if w > maxv
  15. 		maxv=w
  16. 		maxi=n		
  17. 	end
  18. }
  19. p ["value = ",maxv]
  20. p ["index = ",maxi]
  21.  
Success #stdin #stdout 0.21s 7412KB
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["value = ", 239]
["index = ", 7421]
https://ideone.com/thhLQG
language:
Ruby (ruby 2.5.5)
created:
10 years ago
visibility:
public

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