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  1. #include <stdio.h>
  2.  
  3. int main()
  4. {
  5.     int T[5] = {2, 7, 12, 43, 60};
  6.     int low = 0, high = 4;
  7.     int mid;
  8.     int key = 7;
  9.     int location = -1;
  10.  
  11.     printf("输入的5个数字为：\n");
  12.  
  13.     for(int i = 0; i < 5; i++)
  14.     {
  15.         printf("%d ", T[i]);
  16.     }
  17.  
  18.     printf("\n查找关键字：%d\n", key);
  19.  
  20.     while(low <= high)
  21.     {
  22.         mid = (low + high) / 2;
  23.  
  24.         if(T[mid] == key)
  25.         {
  26.             location = mid + 1;
  27.             break;
  28.         }
  29.         else if(T[mid] > key)
  30.         {
  31.             high = mid - 1;
  32.         }
  33.         else
  34.         {
  35.             low = mid + 1;
  36.         }
  37.     }
  38.  
  39.     if(location != -1)
  40.         printf("关键字的位置是：%d\n", location);
  41.     else
  42.         printf("查找失败！\n");
  43.  
  44.     return 0;
  45. }
  46.  
Success #stdin #stdout 0.01s 5328KB
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stdin
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Standard input is empty
stdout
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输入的5个数字为：
2 7 12 43 60 
查找关键字：7
关键字的位置是：2
https://ideone.com/tt403R
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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