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  1. #include<stdio.h>
  2. int main(){
  3.     int a,b=0,n;
  4.     scanf("%d",&n);
  5.     if(n>=0){
  6.     while(n!=0){
  7.         a=n%10;
  8.         n=n/10;
  9.         b=10*b+a;
  10.         }
  11.     printf("该数的逆序数为%d",b);
  12.     }
  13.     else{
  14.         n=-1*n;
  15.         while(n!=0){
  16.         a=n%10;
  17.         n=n/10;
  18.         b=10*b+a;
  19.         }
  20.     printf("该数的逆序数为-%d",b);
  21.     }
  22.     return 0;
  23. }
Success #stdin #stdout 0s 5324KB
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stdin
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-18926105265
stdout
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该数的逆序数为-1806326471
https://ideone.com/rL1Tl4
language:
C (clang 8.0)
created:
8 hours ago
visibility:
public

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