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  1. #include<stdio.h>
  2. int dyg(double a)
  3. { 
  4.    float x0,x1;
  5.    x0=a/2;
  6.    x1=0.5*(x0+a/x0);
  7.    while(fabs(x1-x0)>1e-5)
  8.    {
  9.        x0=x1;
  10.        x1=0.5*(x0+a/x0);
  11.    }
  12.       return x1;
  13. }
  14.  
  15. int main(void) {
  16. 	// your code goes here
  17.     double a;
  18.     float x;
  19.     scanf("%lf",&a);
  20.     x=dyg(a);
  21.     printf("%lf的算术平方根是:%f",a,x);
  22. 	return 0;
  23. }
  24.  
Success #stdin #stdout 0s 5340KB
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2.000000的算术平方根是:1.000000
https://ideone.com/lAtiSH
language:
C (gcc 8.3)
created:
13 hours ago
visibility:
public

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