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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. using int64 = long long;
  4.  
  5. namespace solve {
  6. const int N = 1000000 + 10;
  7. std::vector<int> divs[N];
  8. std::vector<std::pair<int, int>> edges[N];
  9. int p[N], m;
  10. int64 f[N], mu[N];
  11. void init() {
  12. for (int i = 1; i < N; ++i) {
  13. for (int j = i; j < N; j += i) {
  14. divs[j].push_back(i);
  15. }
  16. }
  17. mu[1] = 1;
  18. m = 0;
  19. for (int i = 2; i < N; ++i) {
  20. if(!p[i]) p[m++] = i, mu[i] = -1;
  21. for (int j = 0; i * p[j] < N && j < m; ++j) {
  22. p[i * p[j]] = 1;
  23. if (i % p[j]) mu[i * p[j]] = -mu[i];
  24. else {
  25. mu[i * p[j]] = 0;
  26. break;
  27. }
  28. }
  29. }
  30. }
  31. void run(int n) {
  32. for (int i = 1; i <= n; ++i) {
  33. edges[i].clear();
  34. f[i] = n / i;
  35. }
  36. int64 ret = 0, A = 0, B = 0;
  37. for (int i = 1; i <= n; ++i) {
  38. ret += mu[i] * f[i] * f[i] * f[i];
  39. //cout<<"I:mu["<<i<<"] * f["<<i<<"] * f["<<i<<"] * f["<<i<<"]="<<mu[i] * f[i] * f[i] * f[i]<<endl;
  40. }
  41. std::vector<int> from, to, wei;
  42. m = 0;
  43. std::vector<int> deg(n + 1);
  44. for (int i = 1; i <= n; ++i) {
  45. if (!mu[i]) continue;
  46. for (int j = i; j <= n; j += i) {
  47. if (mu[j] && mu[j / i]) {
  48. for (auto &&k: divs[j / i]) {
  49. int x = i * k, y = j / k;
  50. if (x >= y) continue;
  51. deg[x]++;
  52. deg[y]++;
  53. B += (mu[x] * f[y] + mu[y] * f[x]) * f[j] * f[j];
  54. // cout<<"3B:(mu["<<x<<"] * f["<<y<<"] + mu["<<y<<"] * f["<<x<<"]) * f["<<j<<"] * f["<<j<<"]="<<(mu[x] * f[y] + mu[y] * f[x]) * f[j] * f[j]<<endl;
  55. from.push_back(x);
  56. to.push_back(y);
  57. wei.push_back(f[j]);
  58. ++m;
  59. }
  60. }
  61. }
  62. }
  63. for (int i = 0; i < m; ++i) {
  64. int u = from[i], v = to[i], w = wei[i];
  65. //cout<<u<<" "<<v<<" "<<w<<endl;
  66. if (deg[u] < deg[v]) edges[u].emplace_back(v, w);
  67. else edges[v].emplace_back(u, w);
  68. }
  69. std::vector<int> mark(n + 1, -1);int tri=0,n_edg=0;
  70. for (int a = 1; a <= n; ++a) {
  71. for (auto &&e: edges[a]) mark[e.first] = e.second;
  72. for (auto &&e: edges[a]) {n_edg++;
  73. int b = e.first, w1 = e.second;
  74. for (auto &&ee: edges[b]) {
  75. int c = ee.first, w2 = ee.second;
  76. if (mark[c] != -1) {
  77. A += mu[a] * mu[b] * mu[c] * w1 * w2 * mark[c];
  78. // cout<< "w2=" << w2 << " mark[c]=" << mark[c]<<endl;
  79. // cout<<"6A:mu["<<a<<"] * mu["<<b<<"] * mu["<<c<<"] * "<<w1<<" * "<<w2<<" * mark["<<c<<"]="<<mu[a] * mu[b] * mu[c] * w1 * w2 * mark[c]<<endl;
  80. tri++;
  81. }
  82. }
  83. }
  84. for (auto &&e: edges[a]) {mark[e.first] = -1;
  85. //cout<<"a="<<a<<" e(f,s)=("<<e.first<<","<<e.second<<")"<<endl;
  86. }
  87. }
  88. ret += A * 6 + B * 3;
  89. // printf("%lld\n", ret);
  90. cout<<n<<" "<<n_edg<<" "<<pow(n_edg,1.5)<<" "<<tri<<" "<<pow(n_edg,1.5)/tri<<endl;
  91. }
  92. }
  93.  
  94. int main() {
  95. solve::init();
  96. int n;
  97. //scanf("%d", &n);
  98. for(int n=999999;n<=1000000;n++)
  99. solve::run(n);
  100. return 0;
  101. }
  102.  
Success #stdin #stdout 9.81s 447692KB
stdin
6
stdout
999999 10010249 3.16714e+10 436654181 72.532
1000000 10010249 3.16714e+10 436654181 72.532