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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3.  
  4. int main()
  5. {
  6.     int soma = 0, i, num;
  7.     scanf("%i", &num);
  8.     if (num > 0) {
  9.         for (i = 3; i <= num; i=i+6) {
  10.             printf("%i ", i);
  11.             soma+=i;
  12.         }
  13.     } else {
  14.         for (i = -3; i >= num; i=i-6) {
  15.             printf("%i ", i);
  16.             soma+=i;
  17.         }
  18.     }
  19.     printf("\nSoma: %i", soma);
  20.  
  21.  
  22.     return 0;
  23. }
  24.  
Success #stdin #stdout 0s 4496KB
comments (?)
stdin
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-30
stdout
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-3 -9 -15 -21 -27 
Soma: -75
https://ideone.com/gYWRUF
Soma dos ímpares múltiplos de 3
language:
C (gcc 8.3)
created:
5 years ago
visibility:
public

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