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  1. utime = 172200
  2. uid = [
  3.     {
  4.       "id": 52,
  5.       "time": 172100
  6.     },
  7.     {
  8.       "id": 58,
  9.       "time": 172120
  10.     },
  11.     {
  12.       "id": 33,
  13.       "time": 172153
  14.     },
  15.     {
  16.       "id": 75,
  17.       "time": 172150
  18.     },
  19.     {
  20.       "id": 73,
  21.       "time": 172210
  22.     }
  23.   ]
  24. print(min(uid, key=lambda d: ((diff := utime - d['time']) <= 0, diff)))
Success #stdin #stdout 0.03s 9584KB
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{'id': 33, 'time': 172153}
https://ideone.com/gDKJ6A
language:
Python 3 (python  3.12)
created:
1 year ago
visibility:
secret

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