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  1. #include <stdio.h>
  2.  
  3. int main() {
  4.     int n, i, count = 0;
  5.  
  6.     printf("Enter n: ");
  7.     scanf("%d", &n);
  8.  
  9.     printf("Factors: ");
  10.     for (i = 1; i <= n; i++) {
  11.         if (n % i == 0) {
  12.             printf("%d", i);
  13.             count++;
  14.  
  15.             if (i < n) {
  16.                 printf(", ");
  17.             }
  18.         }
  19.     }
  20.  
  21.     printf("\nNumber of factors: %d\n", count);
  22.  
  23.     return 0;
  24. }
Success #stdin #stdout 0.01s 5268KB
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stdin
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Standard input is empty
stdout
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Enter n: Factors: 1, 3, 5, 9, 15, 45, 491, 1473, 2455, 4419, 7365, 22095
Number of factors: 12
https://ideone.com/dnzHvm
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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