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  1. def max3(x):
  2. 	tmp=[]
  3. 	for a in x:
  4. 		if tmp==[]:
  5. 			tmp=[a]
  6. 		else:
  7. 			tmq=[]
  8. 			for i in range(len(tmp)):
  9. 				if a > tmp[i]:
  10. 					tmq=tmq+[a]+tmp[i:]
  11. 				else:
  12. 					tmq=tmq+[tmp[i]]
  13. 			tmp=tmq[0:3]
  14. 	return tmp
  15.  
  16. print(max3([1,2,3,5,12,4,5,-7,22]))	
  17.  
Success #stdin #stdout 0.02s 9172KB
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stdin
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Standard input is empty
stdout
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[22, 12, 5]
https://ideone.com/bMJmXG
Три максимума
language:
Python 3 (python  3.12)
created:
6 years ago
visibility:
public

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